7v^2-7v+1=0

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Solution for 7v^2-7v+1=0 equation: 



7v^2-7v+1=0

a = 7; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·7·1
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{21}}{2*7}=\frac{7-\sqrt{21}}{14}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{21}}{2*7}=\frac{7+\sqrt{21}}{14}
$

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